09 CALENDAR

"1 >>What is the number of odd days in a leap year? ?

• (A) 1
• (B) 2
• (C) 3
• (D) 4

Solution A leap year has 366 days.Now if we divide 366 by 7 it gives 2 as remainder.Hence number of odd days in 366 days is 2.

2 >>1.12.91 is the first Sunday. Which is the fourth Tuesday of December 91? ?

• (A) 17.12.91
• (B) 24.12.91
• (C) 26.12.91
• (D) 31.12.91

Solution 1.12.91 is the first Sunday of December 91.So, 3.12.91 is the first Tuesday of the month.Clearly, 10.12.91, 17.12.91, 24.12.91 and 31.12.91 are also Tuesdays. So, 24.12.91 is the fourth Tuesday.

3 >>If the day before yesterday was Thursday, when will Sunday be? ?

• (A) Tomorrow
• (B) Today
• (C) Day after tomorrow
• (D) Two days after today

Solution If day before yesterday was Thursday, then today is Saturday.Therefore, tomorrow's will be Sunday.

4 >>If Thursday was the day after the day before yesterday five days ago, What is the least number of days ago when Sunday was three days before the day after tomorrow? ?

• (A) Two
• (B) Three
• (C) Four
• (D) Five

Solution Day after the day before yesterday is yesterday.Now, five days ago, yesterday was thursday.So, five days ago, it was Friday. Therefore today is wednesday.Now, three days before the day after tomorrow is yesterday.Now, it is on Monday that we say Yesterday was Sunday.

5 >>The year next to 1990 will have the same calendar as that of the year 1990. ?

• (A) 1992
• (B) 1995
• (C) 1996
• (D) 1998

Solution The year 1990 has 365 days i.e. 1 odd day, year 1991 has 365 days i.e., odd day, year 1992 has 366 days i.e., 2 odd days.Likewise year 1993, 1994, 1995 have 1 odd day each.The sum of odd days so calculated from year 1990 to 1995( 1 + 1 + 2 + 1 + 1 + 1 ) = 7 odd days.Hence the year 1996 will have the same calendar as that of the year 1990.

6 >>If the second day of a month is a Friday, which of the following would be the last day of the next month which has 31 days? ?

• (A) Sunday
• (B) Monday
• (C) Wednesday
• (D) Data inadequate

Solution The number of days in the current month is not mentioned.

7 >>If 18th February, 1997 falls on Tuesday then what will be the day on 18th February, 1999? ?

• (A) Monday
• (B) Tuesday
• (C) Wednesday
• (D) Thursday

Solution 18th February, 1997 was Tuesday.So, 18th February, 1998 was Wednesday.Therefore, 18th February, 1999 will be Thursday.

8 >>If the day before yesterday was Saturday, What day will fall on the day after tomorrow? ?

• (A) Friday
• (B) Tuesday
• (C) Thursday
• (D) Wednesday

Solution If day before yesterday was Saturday, then today is Monday.Thus tomorrow will be Tuesday and day after tomorrow will be Wednesday.

9 >>If 3rd December, 1990 is Sunday, What day is 3rd January 1991? ?

• (A) Sunday
• (B) Monday
• (C) Tuesday
• (D) Wednesday

Solution Clearly, 3rd, 10th, 17th, 24th and 31st December 1990 are Sundays.So, 1st January 1991 is Monday and 3rd January 1991 is Wednesday

10 >>If the seventh day of a month is three days earlier than Friday, What day will it be on the nineteenth day of the month? ?

• (A) Sunday
• (B) Tuesday
• (C) Wednesday
• (D) monday

Solution The seventh day of the month is three days earlier than Friday, which is Tuesday.So, the fourteenth day is also Tuesday and thus, the nineteenth day is Sunday.

11 >>If every second Saturday and all Sundays are hoildays in a 30 days month beginning on Saturday, then how many working days are there in that month? ?

• (A) 15
• (B) 18
• (C) 23
• (D) 25

Solution Since the month begins on Saturday, so 2nd, 9th, 16th, 23rd, 30th days are Sundays.While 8th and 22nd days are second Saturdays. Thus, there are 7 holidays in all.Therefore number of working days = 30 - 7 = 23.

12 >>What was the day of the week on 24th July 2011? ?

• (A) Monday
• (B) Sunday
• (C) Friday
• (D) None of these

Solution 24 July 2011 = ( 2010 years + Period from 1. 1. 2011 to 24 . 7 . 2011) Odd days in 2000 years = 0 10 years = 8 ordinary years + 2 leap year = ( 8 * 1 + 2 * 2 ) = 8 + 4 = 12 days = 1 week + 5 days = 5 odd days Jan. Feb. March April May June July = ( 31 + 28 + 31 + 30 + 31 + 30 + 24 ) = 205 days 205 days = (29 weeks + 2 day) = 2 odd days. Total number of odd days = (0 + 5 + 2 ) = 7 = 0 odd day. Given day is Sunday

13 >>What was day of the week on 21-September-1987? ?

• (A) Sunday
• (B) Monday
• (C) Friday
• (D) Saturday

Solution 21 September 1987 = ( 1900 years + 86 years + Period from 1 . 1 . 1987 to 21 . 9 .1987) Odd days in 1600 years = 0 Number of odd days in 300 years = 1 odd day. 86 years = 65 ordinary years + 21 leap year = ( 65 * 1 + 21 * 2 ) = 65 + 42 = 107 days 107 days = 15 weeks + 2 days = 2 odd days Jan. Feb. March April May June July Aguest September = ( 31 + 28 + 31 + 30 + 31 + 30 + 31 + 31 + 21 ) = 264 days 264 days = (37 weeks + 5 day) = 5 odd days. Total number of odd days = (0 + 1 + 2 + 5 ) = 8 days 8 days = 1 week + 1 day = 0 odd day. Given day is Sunday

14 >>What was the day of the week on 26-January- 2018? ?

• (A) Sunday
• (B) Monday
• (C) Wednesday
• (D) Friday

Solution 26 January 2018 = ( 2000 years + 17 years + Period from 1. 1. 2018 to 26 . 1 . 2018 ) Number of odd days in 2000 years = 0 odd days 17 years = 13 ordinary years + 4 leap year = ( 13 * 1 + 4 * 2 ) = 13 + 8 = 21 days 21 days = 3 weeks + 0 days = 0 odd days 26 days = ( 3 weeks + 5 days ) = 5 odd days Total number of odd days = (0 + 0 + 5 ) = 5 days given day is Friday.

15 >>Today is Monday, after 61 days, the day will be: ?

• (A) Wednesday
• (B) Saturday
• (C) Tuesday
• (D) Thursday

Solution Each day of the week is repeated after 7 days. So, after 63 days, it will be Monday. After 61 days, it will be saturday.

16 >>Today is Thursday , after 365 days, the day will be: ?

• (A) Wednesday
• (B) Saturday
• (C) Tuesday
• (D) Friday

Solution 365 /7 = 52 weeks + 1 days Each day of the week is repeated after 7 days. So, after 364 days( 52 weeks) , it will be Thursday. After 365 days, it will be Friday.

17 >>If 6th March, 2005 is Sunday, what was the day of the week on 6th March, 2004? ?

• (A) Sunday
• (B) Saturday
• (C) Tuesday
• (D) Wednesday

Solution 6. 3 . 2004 = ( 2000 years + 3 years + Period from 1. 1 2004 to 6 . 3 . 2004 ) Odd days in 2000 years = 0 Number of odd days in 3 years = 3 odd day. Jan. Feb. March = ( 31 + 29 + 6 ) = 66 days 66 days = 9 weeks + 3 days = 3 odd days Total number of odd days = (0 + 3 + 3 ) = 6 days Given day in Saturday

18 >>How many years have 29 days in February from 2001 to 2100. ?

• (A) 26
• (B) 25
• (C) 23
• (D) 24

Solution 100th year is not a leap year. So 24 February’s has 29 days

19 >>March 1st is Wednesday. Which month of the same year starts with the same day? ?

• (A) October
• (B) November
• (C) December
• (D) None of these

Solution Count the number of odd days from the month March onwards to get the sum equal to 0 odd day. Month : Mar April May June July Aug Sept. Oct.Odd dys : 3 3 2 3 3 2 3Total number of odd day = 3 + 2+ 3 + 2 + 3 + 3 + 2 +3 = 21 days. 21 days = 3 week + 0 day = 0. So November has start with the same day.

20 >>What was the day on 2nd Jan 1901 ? ?

• (A) Tuesday
• (B) Wednesday
• (C) Monday
• (D) Thursday

Solution 2nd January 1901 = ( 1900 years + 1 years + 2 days ) Odd days in 1600 years = 0 Number of odd days in 300 years = 1 odd day. 2 days = 2 odd day Total no. of odd days = 0 + 1 + 2 = 3 days Hence, the day on 2nd Jan 1901 was Wednesday.

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